Rymer chairs the advisory committee for an American Association for the Advancement of Science (AAAS) pilot project that offers independent science experts to judges.
So now we have the leading digit of 3 or greater counting the zeroes, a 2 counting the 1s, and two 1s – one to count the 2s and another to count the leading digit.
If we add together all the digits besides the first one – and remember, zeroes don’t increase the sum – we get a count of how many non-zero digits appear in the sequence, including that leading digit.
So if I multiply that by like e to the minus p squared, some normal, it wouldn't look like e to the minus p squared anymore because I've got all that leading p exponentiated and 1 minus p exponentiated.
因此,如果我将其乘以 e 负 p 平方,有些正常,看起来就不再像 e 负 p 平方了,因为我已经得到了所有前导 p 幂次方和 1 负 p 幂次方。